Question

A container has O2 at 5 atm and molar volume 2 liter/mole, if a = 9.24 atm(liter/mole), b = 0.0907 liter/mole, what is the temperature of O2? (Use vander waal equation)

(a) 140 K

(b) 150 K

(c) 170 K

(d) 190 K

I had been asked this question in examination.

The doubt is from Equations of State topic in section Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer 1

Right answer is (c) 170 K

To explain I would say: (p + a/V^2)(V – b) = RT, => T = (5 + 9.24/2^2)(2 – 0.0907)/0.0821 = 170 K.