Question

Maclaurin’s Theorem is a special type of Taylor’s Theorem.

(a) False

(b) True

The question was posed to me during an interview.

My question is based upon Generalized Mean Value Theorem topic in division Differential Calculus of Engineering Mathematics

Answer 1

Correct choice is (b) True

Easiest explanation: The Taylor series expansion of f(x) about x=a is,

f(x)= f(a)+(x-a) f'(a)+(x-a)^2\(\frac{f”}{2!}\) (a)+⋯

If we put x=0, we get the Maclaurin series which is given by, f(x)= f(0)+xf'(0)+x^2 \(\frac{f”}{2!}\) (0)+⋯