The correct choice is (a) 0
For explanation I would say: The maximum array factor occurs when \(\frac{sin \frac{Nφ}{2}}{\frac{Nφ}{2}}\) maximum that is \(\frac{Nφ}{2}=0.\)
And φ=kdcosθ+β
=> kdcosθ+β=0 For a broadside maximum radiation is normal to axis of array so θ=90
=> β=0