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Find the directivity when the half power beam widths are 45° and 60° in perpendicular planes.

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Find the directivity when the half power beam widths are 45° and 60° in perpendicular planes.

(a) 12.58

(b) 17.98

(c) 22.91

(d) 15.28

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This interesting question is from Half Power Beam Width in portion Antenna Beam Width & Input Impedance of Antennas

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The correct option is (d) 15.28

Easy explanation: Directivity in terms of HPBW (in degrees) is given by \(D=\frac{41257}{θ_E θ_H} =\frac{41257}{45° × 60°}=15.28\)

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