Question

Find the skip distance when the angle of incidence is 200 and virtual height is 50km?

(a) 13.22m

(b) 13.22km

(c) 36.33km

(d) 36.33m

The question was posed to me in a job interview.

This interesting question is from Virtual Height in division Virtual Height, Critical Frequency and Muf of Antennas

Answer 1

Right answer is (c) 36.33km

Easy explanation: Skip distance \(d=2h\sqrt{[\frac{f_{MUF}^2}{f_c^2}-1]}=2h\sqrt{[secθ_i^2-1]} =2×50×\sqrt{[(sec20)^2-1]}\)

d=36.33km