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What is the standard value for the radius of curvature rc to be equal to the radius of earth re?

(a) rc=4re

(b) rc=\(\frac{4r_e}{3}\)

(c) rc=re

(d) rc=\(\frac{1}{4}\) re

I had been asked this question during an interview.

The origin of the question is Space Wave Propagation topic in section Space Wave Propagation of Antennas

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The correct answer is (a) rc=4re

For explanation: The radius of curvature is four times the radius of earth. rc=4re

The effective radius factor of earth is 4/3 times actual radius of earth.

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