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Simplify the given grammar: A-> a| aaA| abBc B-> abba| b

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in Automata Theory by (51.1k points)
Simplify the given grammar:

A-> a| aaA| abBc

B-> abba| b

(a) A-> a| aaA| ababbAc| abbc

(b) A-> a| aaA| ababbAc| abbc, B-> abba|b

(c) A-> a| aaA| abbc, B->abba

(d) None of the mentioned

The question was asked in an online interview.

My enquiry is from CFG-Eliminating Useless Symbols in division Properties of Context Free Languages of Automata Theory

1 Answer

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Best answer
Correct choice is (a) A-> a| aaA| ababbAc| abbc

For explanation I would say: Using the substitution rules, we can simply eradicate what is useless and thus produce the simplified result i.e. A-> a| aaA| ababbAc| abbc.

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