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Pointer to a base class can be initialized with the address of derived class, because of _________

(a) derived-to-base implicit conversion for pointers

(b) base-to-derived implicit conversion for pointers

(c) base-to-base implicit conversion for pointers

(d) derived-to-derived implicit conversion for pointers

I have been asked this question by my school teacher while I was bunking the class.

I want to ask this question from Pointer to Objects topic in section Assigning Object, Pointer to Objects, Passing and Returning Object of Object Oriented Programming

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Right answer is (a) derived-to-base implicit conversion for pointers

The explanation is: It is an implicit rule defined in most of the programming languages. It permits the programmer to declare a pointer to the derived class from a base class pointer. In this way the programmer doesn’t have to declare object for derived class each time it is required.

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