Question

If the wheelbase, the pivot center, and wheel track of the are 2.5 m, 1.1 m, and 1.3 m respectively. The angle of the inside lock is 42℃. What is the circle radius of the outer front wheel?

(a) 2.6 m

(b) 3.6 m

(c) 4.6 m

(d) 1.6 m

I got this question during an interview for a job.

My enquiry is from Steering System in portion Steering & Front Axle of Automobile Engineering

Answer 1

The correct option is (b) 3.6 m

The explanation is: b = wheelbase = 2.5 m, c = pivot center = 1.1 m, a = wheel track = 1.3 m, and θ = angle of inside lock = 42℃. For the inner front wheel, radius =\(\frac{b}{sin⁡\theta} – \frac{a – c}{2} = \frac{2.5}{sin⁡42} – \frac{1.3 – 1.1}{2}\) = 3.6 m