Question

What is the brake power if the swept volume is 3.5 liters, brake mean effective pressure is 10 bars, and speed is 6000 rpm?

(a) 175 kW

(b) 17.5 kW

(c) 1.75 kW

(d) 1750 kW

I have been asked this question by my school principal while I was bunking the class.

The query is from Supercharging of IC Engines topic in division Fuels & Supercharging of I.C of Automobile Engineering

Answer 1

Correct choice is (a) 175 kW

To elaborate: Given swept volume = 3.5 liters, brake mean effective pressure = 10 bars & speed = 6000 rpm.

Brake power = \(\frac{brake \,mean \,effective \,pressure \,X \,swept \,volume \,X \,no.of \,cylinder \,X \,no.of \,power \,strokes}{60000} \)

= \(\frac{3.5 × 10 × 10^5 × 6000}{1000 × 60000 × 2}\) = 175 kW.