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In an engine running at 2200RPM has BP=35KW and FP=3KW, what is the value of IP?

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In an engine running at 2200RPM has BP=35KW and FP=3KW, what is the value of IP?

(a) 38KW

(b) 38MW

(c) 32KW

(d) 32MW

The question was posed to me in class test.

This intriguing question comes from IC Engine topic in portion Design of IC Engine Components of Automotive Engine Design

1 Answer

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The correct option is (a) 38KW

To explain I would say: IP=BP+FP

       IP=35KW+3KW

                            =38KW

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