Right choice is (c) th=\(\frac{H}{12.56K(T_c-T_e)}\) × 10^3
Explanation: th is the thickness of the piston head, H is the Heat conducted, K is thermal conductivity factor, Tc-Te is the temperature from the center to edge of the piston. When all these are summed, we get th=\(\frac{H}{12.56K(T_c-T_e)}\times 10^3\).