Question

Mass and volume of an object is dependent on its temperature in kelvin as m = 5t^2 kg and v = (400 + 600t) m^3 respectively, then what is the density of the object at t = 27^oC?

(a) 5 kg/m^3

(b) 10 kg/m^3

(c) 15 kg/m^3

(d) 20 kg/m^3

This question was posed to me in a job interview.

This question is from Temperature topic in section Temperature and Pressure of Basic Chemical Engineering

Answer 1

Correct choice is (a) 5 kg/m^3

The best explanation: Density of object = dm/dv = (dm/dt)/(dv/dt) = 10t/600 = t/60, => density of object at t = 27^oC = 300 K is D = 300/60 = 5 kg/m^3.