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In a steady-state reactive system, NaOH and HCl are supplied to the system both at the rate of 100 mole/min, then what is the rate of NaCl produced?

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In a steady-state reactive system, NaOH and HCl are supplied to the system both at the rate of 100 mole/min, then what is the rate of NaCl produced?

(a) 100 mole/min

(b) 200 mole/min

(c) 300 mole/min

(d) 400 mole/min

This question was addressed to me during a job interview.

Query is from Accounting for Chemical Reactions in Material Balances topic in section Introduction to Material Balances of Basic Chemical Engineering

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The correct option is (b) 200 mole/min

Explanation: As the system is in steady-state, rate of product = rate of feed, => rate of NaCl = 100 + 100 = 200 mole/min.

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