Question

A reactor is supplied with C6H12O6 and the following reactions occur C6H12O6 -> 2C2H5OH + 2CO2 and C6H12O6 –> 2C2H3CO2H + 2H2O, 360 grams of pure glucose is supplied and 44 grams of CO2 was produced, what 90 grams of glucose left unreacted, how many grams of propenoic acid was produced?

(a) 18

(b) 36

(c) 72

(d) 144

This question was addressed to me in an interview for internship.

I'm obligated to ask this question of Processes Involving Multiple Units topic in division The Chemical Reaction Equation & Stoichometry, Material Balances for Processes Involving Reaction and Multiple Units of Basic Chemical Engineering

Answer 1

Correct answer is (d) 144

The explanation: Weight of glucose reacted in first reaction = (44/44)*(1/2)*180 = 90 grams, => (360 – 90 – 90) = 180 grams of glucose reacted in second reaction, => weight of propenoic acid produced = 2*(180/180)*72 = 144 grams.