Question

A material’s mass is given by the equation, m = 32P^0.02/T^0.5, where T is in Kelvin, m is in Kg and P is in mm Hg, what is the mass of material at 127^oC, use A = 10, B = 6 X 10^3 and C = 0?

(a) 1.44 Kg

(b) 1.69 Kg

(c) 1.96 Kg

(d) 2.25 Kg

The question was asked by my college professor while I was bunking the class.

My question is based upon Modeling and Predicting Vapor Pressure topic in division Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer 1

Right option is (a) 1.44 Kg

Explanation: ln p* = A – B/(C + T) = 10 – 6 X 10^3/(400) = -5, => p = 0.0067 mm Hg, => m = 32*(0.0067)^0.02/400^0.5 = 1.44 Kg.