Question

Heat Capacity of CO2 is given by 12 + 3T + T^2, what is the enthalpy change from 0^oC to 6^oC?

(a) 169 J

(b) 198 J

(c) 244 J

(d) 360 J

This question was addressed to me in an online interview.

Asked question is from Heat Capacity Equations in chapter Introduction to Energy Balances for Processes without Reaction and Calculation of Enthalpy Changes of Basic Chemical Engineering

Answer 1

The correct answer is (b) 198 J

The explanation is: ∆H = 0∫^6 (12 + 3T + T^2).dT = 12*6 + 3*36/2 + 63/3 = 198 J.