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What is the enthalpy change of a reaction at 45^oC, if the enthalpy of reactant at 45^oC and 25^oC are 10 J and 6 J, and enthalpy of product at 45^oC and 25^oC are 15 J and 8 J, and the enthalpy change of reaction at 25^oC is 10 J?

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What is the enthalpy change of a reaction at 45^oC, if the enthalpy of reactant at 45^oC and 25^oC are 10 J and 6 J, and enthalpy of product at 45^oC and 25^oC are 15 J and 8 J, and the enthalpy change of reaction at 25^oC is 10 J?

(a) 14 J

(b) 21 J

(c) 27 J

(d) 34 J

The question was posed to me in unit test.

This key question is from Heat (Enthalpy) of Reaction in portion Application of Energy Balances in the Absence of Chemical Reactions and Energy Balances: How to Account for Chemical Reaction of Basic Chemical Engineering

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The correct answer is (b) 21 J

The explanation: Heat of reaction = (10 – 6) + (15 – 8) + 10 = 21 J.

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