Question

K1 and K2 for oxalic acid are 6.5×10^-2and 6.1×10^-5respectively. What will be the [OH^–] in a 0.01M solution of sodium oxalate?

(a) 9.6×10^-6

(b) 1.4×10^-1

(c) 1.2×10^-6

(d) 1.3×10^-8

I have been asked this question in an interview for internship.

My query is from Ionization of Water, Weak acids and Weak Bases in section Water Basics of Biochemistry

Answer 1

Correct option is (c) 1.2×10^-6

To explain: The hydrolysis of C2 O4^2- is as follows

  C2 O4^2-+ H2 O → HC2O^4- + OH^–