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For the given manometer

(a) P1 + ρ1d2g = P2 + ρ2d2g

(b) P1 + ρ1d1g = P2 + ρ2d2g

(c) P1 + ρ1d1g = P2 + ρ2d2g + ρ3d3g

(d) None of the mentioned

I got this question in an interview for internship.

The above asked question is from Pressure and Hydrostatic Head-I in portion Introductory Concepts of Chemical Process Calculation

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The correct option is (c) P1 + ρ1d1g = P2 + ρ2d2g + ρ3d3g

To explain I would say: P1 + ρ1d2g = P2 + ρ2d2g + ρ3d3g. For same liquid at same level, pressure will be always same.

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