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If the required amount of water is 72 kg then how much C6H14 should be burned per hour?

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in Chemical Process Calculation by (98.7k points)
If the required amount of water is 72 kg then how much C6H14 should be burned per hour?

(a) 49.14

(b) 39.14

(c) 39.14

(d) 29.14

The question was posed to me in an interview for internship.

My question is from Stoichiometry-II topic in division Material Balances without Reaction and Material Balances Involving Reactions of Chemical Process Calculation

1 Answer

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Best answer
Right answer is (a) 49.14

Easiest explanation: 1 mole of C6H14 = 7 moles of H2O.

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