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What is the formula for a solid compound that contains 42.11% C, 51.46% O, and 6.43% H and having molecular weight about 341.

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What is the formula for a solid compound that contains 42.11% C, 51.46% O, and 6.43% H and having molecular weight about 341.

(a) C10 O12H29

(b) C11O13 H

(c) C12O11H22

(d) C12O10H37

This question was addressed to me in semester exam.

This interesting question is from Mole and Molecular Weight-III topic in chapter Introductory Concepts of Chemical Process Calculation

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The correct option is (c) C12O11H22

Easiest explanation: Take 100 g of the compound and calculate the ratio of the molecules, then make it integer to get the chemical formula.

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