Question

Calculate the actual permittivity of a medium whose relative permittivity is 5.

(a) 4.43*10^-11F/m

(b) 4.43*10^-12F/m

(c) 4.43*10^11F/m

(d) 4.43*10^12F/m

This question was posed to me in a job interview.

This interesting question is from Relative Permittivity in section Capacitance and Capacitors of Basic Electrical Engineering

Answer 1

Right option is (a) 4.43*10^-11F/m

Best explanation: Actual permittivity = Relative permittivity*absolute permittivity.

Actual permittivity = 5*8.85*10^-12 = 4.43*10^-11F/m.