Question

I1 is the current flowing in the first mesh. I2 is the current flowing in the second mesh and I3 is the current flowing in the top mesh. If all three currents are flowing in the clockwise direction, find the value of I1, I2 and I3.

(a) 7.67A, 10.67A, 2A

(b) 10.67A, 7.67A, 2A

(c) 7.67A, 8.67A, 2A

(d) 3.67A, 6.67A, 2A

I have been asked this question in final exam.

This interesting question is from Mesh Analysis in section Network Theorems of Basic Electrical Engineering

Answer 1

The correct option is (a) 7.67A, 10.67A, 2A

To explain: The two meshes which contain the 3A current is a super mesh. The three mesh equations therefore are:

I3=2A

I2-I1=3

-2I1-I2=-26

Solving these equations simultaneously we get:

I1=7.67A, I2=10.67A and I3=2A.