Right answer is (a) 0.54A
The explanation: The 3 5 ohm resistors are connected in delta. Changing it to star:
R1=R2=R3 = 1.67 ohm.
One of the 1.67 ohm resistors are connected in series with the 2 ohm resistor and another 1.67 ohm resistor is connected in series to the 3 ohm resistor.
The resulting network has a 1.67 ohm resistor connected in series with the parallel connection of the 3.67 and 4.67 resistors.
The equivalent resistance is 3.725A.
I=2/3.725 = 0.54A.