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If t0.5 = 100 minutes and initial concentration is 10, then the order of the reaction is ____

(a) 4

(b) -1

(c) -2

(d) 1

This question was addressed to me in final exam.

This interesting question is from Rate Data Collection & Analysis in chapter Collection and Analysis of Rate Data of Chemical Reaction Engineering

1 Answer

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Correct answer is (b) -1

For explanation: t0.5 = \(C_{A0}^{1-n}.\)100 = 10^(1 – n). Hence, n = -1.

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