Question

The equation representing the variation of rate constant with respect to temperature by Arrhenius equation is ____

(a) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}  (\frac{1}{T_2} – \frac{1}{T_1}) \)

(b) ln(\(\frac{k_2}{k_1}\)) = \(\frac{E}{R}  (\frac{1}{T_2} – \frac{1}{T_1}) \)

(c) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}  (\frac{1}{T_1}- \frac{1}{T_2}) \)

(d) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}  (\frac{1}{T_2} + \frac{1}{T_1}) \)

I had been asked this question in semester exam.

Asked question is from Kinetics of Homogeneous Reactions topic in portion Kinetics of Homogeneous Reactions of Chemical Reaction Engineering

Answer 1

The correct answer is (a) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}  (\frac{1}{T_2} – \frac{1}{T_1}) \)

For explanation I would say: By Arrhenius equation, k = \(Ae^{\frac{-Ea}{RT}},\) where A is the frequency factor.

For two different temperatures, T1 and T2, the Arrhenius equation is reduced as ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_2} – \frac{1}{T_1}). \)