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A liquid phase reaction occurring in adiabatic PFR has a heat of reaction -120000 J/molK. Specific heat of the stream is 10000 J / molK. The temperature difference for complete conversion to be achieved is ___

(a) 560 K

(b) 8.33 K

(c) 12 K

(d) 83.33K

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This intriguing question originated from RTD for Chemical Reactors topic in section Distribution of Residence Time for Chemical Reactors of Chemical Reaction Engineering

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Best answer
Right option is (c) 12 K

The best explanation: \(\frac{C_p ∆T}{-H_R}\) = XA

XA = 1 for complete conversion.

∆T = \(\frac{120000}{10000}\) = 12 K.

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