Question

The Langmuir Hinshelwood mechanism for equimolar reactant feed is ____

(a) \(\frac{aP}{(1+bP)^2}\) = -r0

(b) \(\frac{P}{(1+bP)^2}\) = -r0

(c) \(\frac{aP}{(bP)^2}\)  = -r0

(d) \(\frac{aP}{(1+bP)}\) = -r0

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Answer 1

The correct choice is (a) \(\frac{aP}{(1+bP)^2}\) = -r0

To explain I would say: A + B → R

If \(\frac{A}{B}\)=1, yA = yB = 0.5 for equimolar feed

-r0 = \(\frac{kP_A P(0.5)(0.5)}{(1+(0.5k_A P)+(0.5k_B P))^2}\) = \(\frac{aP}{(1+bP)^2}. \)

Where, a and b are constants, P is the total pressure.