Question

7(i)+ B(OCH3)3  → NaBH4 + 6(ii)+ 3(iii) Name the compounds i, ii, iii?

(a) i.sodium hydride ii.sodium iii.methanol

(b) i.sodium Ii.methanol iii.sodium hydride

(c) i.sodium ii.sodium hydride iii.methanol

(d) i.sodium hydride ii.methanol iii.sodium

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This key question is from Inorganic Chemical in portion Inorganic Chemical Industries of Chemical Technology

Answer 1

Right choice is (a) i.sodium hydride ii.sodium iii.methanol

To elaborate: The reaction is  7NaH + B(OCH3)3  → NaBH4 + 6Na + 3CH3OH, hence compound i is sodium hydride, compound ii is sodium and compound iii is methanol.