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Modulus of rupture is calculated using the formula:

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in Basic Civil Engineering by (111k points)
Modulus of rupture is calculated using the formula:

(a) f=PL/bd^2

(b) f=PL^3/3EI

(c) f=I/6bd^2

(d) f=Pb/Ld^2

I have been asked this question in an international level competition.

Query is from Tests on Concrete in division Building Construction of Basic Civil Engineering

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Right option is (a) f=PL/bd^2

To elaborate: The modulus of rupture is found out dividing maximum moment M/section factor Z.   M is given by PL/6 and Z=1/6bd^2.

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