Question

Calculate the area of cross section of the multi plate capacitor having C=20F, actual permittivity=5F/m n=3 and d=2m.

(a) 1m^2

(b) 2m^2

(c) 3m^2

(d) 4m^2

The question was posed to me during a job interview.

My query is from Capacitance of a Multi Plate Capacitor in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer 1

Right answer is (d) 4m^2

Easiest explanation: The formula for capacitance of a multi plate capacitor: C=Actual permittivity*(n-1)*A/d.

Substituting the given values in the equation, we get A=4m^2.