Correct choice is (b) 5.21V
The explanation: Assuming i1 and i2 be the currents in loop 1 and 2 respectively. In loop 1, 4+2i1+3(i1-17/3)+4(i1-i2)+5=0
In loop 2, i2(4+1+5)-4i1-5=0 =>-4i1+10i2=5.
Solving these equations simultaneously i2=1.041A and i1=1.352A
V=i2*5= 5.21V.