Question

Calculate d^2i(0)/dt^2 from the given circuit.

(a) 10^-6A/s^2

(b) 10^-3A/s^2

(c) 10^6A/s^2

(d) 10^3A/s^2

I have been asked this question in an interview for job.

Origin of the question is Transients in CR Networks in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer 1

The correct answer is (b) 10^-3A/s^2

The best explanation: Applying KVL to the given circuit, we get:

100+10i(0)+1/10*integral(i(0)dt)=0

Differentiating once, we get:

10di(0)/dt+1/10*i.

Differentiating once again, we get:

10d^2i(0)/dt^2+10di(0)/dt=0.

Substituting the values of di/dt from the previous explanation, we get d^2i(0)/dt^2=10^-3A/s^2.