Question

What is the correct expression for the phase angle in an RLC series circuit?

(a) φ=tan^-1(XL-XC)/R

(b) φ=tan^-1 (XL+XC)/R

(c) φ=tan(XL-XC)/R

(d) φ=tan^-1 (XL-XC)

The question was posed to me in examination.

The doubt is from Alternating Current in an RLC Circuit topic in portion Single Phase Series Circuits of Basic Electrical Engineering

Answer 1

Right answer is (a) φ=tan^-1(XL-XC)/R

To elaborate: from the impedance triangle we get tanφ=(XL-XC)/R.

Hence φ=tan^-1 (XL-XC)/R.