Question

Refer to Q 10 and Q11, and calculate specific volume.

(a) 6.51 × 10^-5 m^3/N

(b) 6.78 × 10^-5 m^3/N

(c) 6.45 × 10^-5 m^3/N

(d) 6.57 × 10^-5 m^3/N

The question was asked by my college director while I was bunking the class.

My question comes from Classification of Fluids in portion Fluid Flow and Mixing of Bioprocess Engineering

Answer 1

Right option is (d) 6.57 × 10^-5 m^3/N

The explanation: Specific volume = 1/(Specific weight)

= 1/(1.52×104 N/m^3)

= 6.57 × 10^-5 m^3/N.