Question

A bioreactor of working volume 50 m^3 produces a metabolite (X) in batch culture under given operation conditions form a substrate (S). The final concentration of metabolite at the end of each run was 1.1kg m^-3. The bioreactor was operated to complete 60 runs in each year. What will be the annual output of the system (production of metabolite (X)) in Kg per year?

(a) 70

(b) 66

(c) 77

(d) 60

I got this question by my school teacher while I was bunking the class.

My doubt stems from Role of Diffusion in Bioprocessing in portion Mass Transfer of Bioprocess Engineering

Answer 1

To calculate the annual output of the system, we can use the following information:

Given Data:

• Bioreactor working volume = 50 m³.
• Final concentration of metabolite (X) = 1.1 kg/m³.
• Number of runs per year = 60.

Step-by-Step Calculation:

1. Metabolite production per run: The amount of metabolite produced per run is the product of the bioreactor volume and the final concentration of the metabolite.

   $$\text{Metabolite produced per run}=\text{Volume of reactor}\times \text{Final concentration of metabolite}$$ Metabolite produced per run=50 m3×1.1 kg/m3=55 kg\text{Metabolite produced per run} = 50 \, \text{m}^3 \times 1.1 \, \text{kg/m}^3 = 55 \, \text{kg}Metabolite produced per run=50m3×1.1kg/m3=55kg

2. Annual output of metabolite: The total annual production is the amount produced per run multiplied by the number of runs per year.

   $$\text{Annual output}=\text{Metabolite produced per run}\times \text{Number of runs per year}$$ $$\text{Annual output}=55\text{kg}\times 60=3300\text{kg/year}$$

Answer:

There seems to be a discrepancy. However, checking for more context:
The metabolite concentration provided does not seem to align with the choices at first glance.