Question

Refer to Q4 and Estimate the amount of enzyme present.

(a) 4.81×10^-8 kg

(b) 4.83×10^-8 kg

(c) 4.85×10^-8 kg

(d) 4.87×10^-8 kg

The question was asked in an interview for job.

My question is based upon Internal Mass Transfer and Reaction in division Heterogenous Reactions of Bioprocess Engineering

Answer 1

Right answer is (b) 4.83×10^-8 kg

For explanation I would say: 10 beads have volume 2.68×10^-6 m^3. The amount of enzyme present is:

2.68 ×10^-6 m^3 (0.018 kgm^-3) = 4.83 × 10^-8 kg.