Right answer is (c) Hyperbolic
For explanation: The second-order wave equation is
\(\frac{\partial^2 u}{\partial t^2}=c^2\frac{\partial ^2 u}{\partial x^2}\)
The general equation is in this form.
A \(\frac{\partial^2 \Phi}{\partial x^2}+B\frac{\partial ^2 \Phi}{\partial x\partial y}+C\frac{\partial^2 \Phi}{\partial y^2}+D\frac{\partial \Phi}{\partial x}+E\frac{\partial\Phi}{\partial y}+F\Phi +G=0\)
Comparing \(\frac{\partial ^2 u}{\partial t^2}-c^2\frac{\partial ^2 u}{\partial x^2}=0\) with the above equation, (let ‘y’ be ‘t’).
A=-c^2
B=0
C=1
To find the type,
d=B^2-4AC
d=4c^2
As d is positive, the second order wave equation is hyperbolic.