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As the metal dissolution within the crevice increases, the rate of oxygen reduction on adjacent surfaces increases.

(a) True

(b) False

The question was asked during an online exam.

I'm obligated to ask this question of Eight Forms topic in section Eight Forms of Corrosion of Corrosion Engineering

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Best answer
Right answer is (a) True

Best explanation: Metallic dissolution in the crevice cathodically protects the external surface.  Electrons transfer from M==>M^+n+ne (in crevice) to compensate O2+H2O+4e==>4OH (adjacent surface).

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