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What is the probability of getting Aa Bb Cc from the cross aa BB cc X AA bb CC?

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What is the probability of getting Aa Bb Cc from the cross aa BB cc X AA bb CC?

(a) 1/4

(b) 1/8

(c) 1

(d) 4

The question was asked in an interview for job.

I'm obligated to ask this question of Numerical Problems topic in division Mendelian Genetics of Cytogenetics

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Correct answer is (c) 1

Best explanation: In this case, all three locus is homozygous dominant for one and homozygous recessive for the other. Thus all the gametes are heterozygous. So considering the calculation it will be 1 X 1 X 1 for A, B and C locus respectively.

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