Question

Find the current in the 3Ω resistor of the given network using Superposition principle.

(a) 2.5A

(b) 3.125A

(c) 6.525A

(d) 5.625A

I had been asked this question in homework.

This is a very interesting question from Maximum Power Transfer and Superposition in division Techniques of Circuit Analysis of Electric Circuits

Answer 1

The correct choice is (d) 5.625A

To elaborate: 1.When 20v source acting alone: current source is replaced by open circuit.  Req= 5+3=8Ω and Current I= 20/8=2.5A

                        2. When 5A source acting alone: 20v source is replaced by a short circuit. By current division rule, I3= 25/8=3.125A

   Total current through I3= 2.5+3.125=5.625A.