Question

The voltage applied to a pure capacitor of 50*10^-6 F is as shown in figure. Calculate the current for 0-1msec.

(a) 5A

(b) 1A

(c) -5A

(d) -1A

The question was asked in exam.

Question is taken from Inductor and Capacitor topic in chapter Inductance, Capacitance, and Mutual Inductance of Electric Circuits

Answer 1

The correct option is (a) 5A

Explanation: For 0≤t≤1msec,

                         V (t) =m*t (y=mx form)

      →100= 1*10^-3*m →m= 1*10^5

      → V (t) = 1*10^5t

Current I (t) = c. d (v (t))/dt = 50*10^-6* (d (1*10^5t)/dt) = 5A.