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Calculate the active power in a .7889 H inductor.

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Calculate the active power in a .7889 H inductor.

(a) .123 W

(b) .155 W

(c) 0 W

(d) .487 W

I got this question in homework.

This question is from Methods of Starting Electric Motors topic in chapter Starting of Electric Drives

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Right choice is (c) 0 W

The best I can explain: The inductor is a linear element. It only absorbs reactive power and stores it in the form of oscillating energy. The voltage and current are 90° in phase in case of the inductor so the angle between V & I is 90°. P = VIcos90° = 0 W.

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