Question

Calculate the energy stored in the capacitor if the voltage across the capacitor is 20 V and capacitance value is 2 F.

(a) 400 J

(b) 200 J

(c) 100 J

(d) 50 J

The question was asked in an interview for internship.

I need to ask this question from Electric Motors in chapter Braking of Electric Motors of Electric Drives

Answer 1

The correct option is (a) 400 J

Explanation: The energy stored in the capacitor is .5×C×V^2. It is the total amount of energy stored in the capacitor in the steady state condition. E=.5×C×V^2=.5×2×20×20=400 J.