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Calculate the circuit turn-off time for Half-wave controlled rectifier for a ω=5 rad/sec for resistive load.

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Calculate the circuit turn-off time for Half-wave controlled rectifier for a ω=5 rad/sec for resistive load.

(a) .62 sec

(b) .42 sec

(c) .58 sec

(d) .64 sec

I got this question in an international level competition.

This question is from Solid-State Switching Circuits topic in division Introduction to Solid-State Switching Circuits of Electric Drives

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Correct answer is (a) .62 sec

Explanation: The value of the circuit turn-off for Half-wave controlled rectifier for a ω=5 rad/sec for the resistive load is a π÷Ω=π÷5=.62 sec.

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