Question

Calculate the r.m.s value of diode current in 1-Φ Full wave semi-converter for the load (Highly inductive) current=5.1 A and α=115°. (Asymmetrical configuration)

(a) 4.21 A

(b) 4.61 A

(c) 4.71 A

(d) 4.52 A

The question was asked in homework.

Query is from Solid-State Switching Circuits in portion Introduction to Solid-State Switching Circuits of Electric Drives

Answer 1

Correct answer is (b) 4.61 A

For explanation I would say: The r.m.s value of diode current in 1-Φ Full wave semi-converter is Io√π+α÷2π. It is the r.m.s value of the diode current. I(r.m.s) = Io√π+α÷π=5.1(√.819)=4.61 A.