Question

Calculate the I0 avg for Single-phase Half Wave rectifier for R-L load using the data: Vm=56 V, ∝=15°, β=30°, R=2 Ω.

(a) .56 A

(b) .44 A

(c) .26 A

(d) .89 A

This question was posed to me in class test.

The origin of the question is Solid-State Switching Circuits topic in section Introduction to Solid-State Switching Circuits of Electric Drives

Answer 1

Correct answer is (a) .56 A

The explanation is: In Half-wave controlled rectifier, the average value of the current is Vm(cos(∝)-cos(β))÷2πR=56(cos(15°)- cos(30°))÷12.56=.44 A. The thyristor will conduct from ∝ to β.