To calculate the output voltage of a buck converter, we use the formula:
Vout=D×VinV_{out} = D \times V_{in}Vout=D×Vin
Where:
- VoutV_{out}Vout is the output voltage,
- DDD is the duty cycle,
- VinV_{in}Vin is the input supply voltage.
Given:
- Vin=13 VV_{in} = 13 \, \text{V}Vin=13V,
- D=0.16D = 0.16D=0.16.
Substituting the values into the formula:
Vout=0.16×13 V=2.08 VV_{out} = 0.16 \times 13 \, \text{V} = 2.08 \, \text{V}Vout=0.16×13V=2.08V
Thus, the output voltage is 2.08 V.
The correct answer is (a) 2.08 V.