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What is the formula for window area of the transformer?

(a) window area = output power * 2.22 * frequency * magnetic field * window space factor * current density * area of cross section of the core *10^3

(b) window area = output power / 2.22 * frequency * magnetic field * window space factor * current density * area of cross section of the core *10^3

(c) window area = output power / 3.33 * frequency * magnetic field * window space factor * current density * area of cross section of the core *10^3

(d) window area = output power * 3.33 * frequency * magnetic field * window space factor * current density * area of cross section of the core*10^3

The question was asked in semester exam.

I need to ask this question from Overall Dimensions in division Design of Transformers of Design of Electrical Machines

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The correct choice is (b) window area = output power / 2.22 * frequency * magnetic field * window space factor * current density * area of cross section of the core *10^3

To explain I would say: The window space factor, the current density and the core cross sectional area are obtained by their respective formula. The frequency is 50Hz and then the magnetic field and the output power is calculated to obtain the window space factor.

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